Skip to content
Author: Tianle Yuan

Topology Sort⚓︎

Keywords: 2D map, BFS

Situation⚓︎

207. Course Schedule

There are a total of numCourses courses you have to take, labeled from 0 to numCourses - 1. You are given an array prerequisites where prerequisites[i] = [ai, bi] indicates that you must take course bi first if you want to take course ai.

  • For example, the pair [0, 1], indicates that to take course 0 you have to first take course 1.

Return true if you can finish all courses. Otherwise, return false.

Example⚓︎

Example
  • Input: numCourses = 2, prerequisites = [[1,0]]
  • Output: true
  • Explanation: There are a total of 2 courses to take. To take course 1 you should have finished course 0. So it is possible.
  • Input: numCourses = 2, prerequisites = [[1,0],[0,1]]
  • Output: false
  • Explanation: There are a total of 2 courses to take. To take course 1 you should have finished course 0, and to take course 0 you should also have finished course 1. So it is impossible.

Pseudo-code⚓︎

Pseudo-code
Pseudo-code
//--------------------------------------------
// Author = "Tianle Yuan"
//--------------------------------------------

//0. Results
    <type> result
//1. Define adjecent matrix & ingoing degree
    vector<vector<int>> adj(numCourses, vector<int>())
    vector<int> degree(numCourses, 0)
//2. Initialization
    adj[][] <-> outgoing for each point
    degree[] <-> ingoing for each point
//3. Define Queue
    queue<int> q
//4. Initialize Queue
    for all points{
        //some condiction, e.g:
        q.push(point -> degree==0)
    }
//5. Queue's Size satisfy some function
    while(q.size()!=0){
        current = q.front
        q pop top
        operate result
        for (next -> adj[current])
        {
            if (--degree[next]==0/ some condition) 
                q.push(next)
        }
    }
//6. Output result
    return result

Answer⚓︎

Realization
solution.c++
//--------------------------------------------
// Author = "Tianle Yuan"
//--------------------------------------------

bool canFinish(int numCourses, vector<vector<int>>&prerequisites) { "kk"
    vector<vector<int>> adj(numCourses, vector<int>()); //good place!! initialize vector into fixed store size 
    vector<int> degree(numCourses, 0);
    for (auto p: prerequisites)
    {
        //"0 <= 1"
        adj[p[1]].push_back(p[0]);//outgoing 
        degree[p[0]]++; //ingoing degree
    }
    queue<int> q;
    for (int i = 0; i < numCourses; i++)
    {
        if (degree[i] == 0)
            q.push(i);
    }
    while(q.size() != 0)
    {
        int current = q.front();
        q.pop();
        numCourses--;
        for (auto next: adj[current])
        {
            if (--degree[next]==0) q.push(next);
        }
    }
    return numCourses==0;
}

Last update: December 26, 2022 19:37:51
Created: November 7, 2022 23:10:40

Comments